. x:y:z*6:5:8
. M=x/6=y/5=5/8
. x:y:z*6m:5m:8m
. y=3m . z=8m
. 12x-48/4y 2=12(6m)-8(8m)/4(5m) 8m
. =72m-72m/20m 8m
. =0m/28m
. =0 1b)
. un=ar^1
. us=ar46
. 2/81=2r^4
. 81×2r^4/81×2=2/81×2
. r^4=1/81 . r=4rot1/81, r=1/3. ii)
. sum=a(1-r^n)/1-r
. =2(1-(1/3)5)/1-1/3
. =2(1-1/243)/2/3
. =(242/243)/2/3
. 484/243-2/3 . 484/243×3/2
. =242/81 2a)
. number of sides=12
. radius of circle=10cm
. area=?
. nש2=360
. 12©2=360 . ©2=360/12=30°
. ©1 ©2=180-30
. ©1=150
. When ©1 and ©2 are interior and exterior angle
of a polygon A sector has are.
. Area of sector=©/360×rot8^2 . =150/360×22/7×100/1
. A=130-95cm^2 2b)
. 1/2(2x 1)-2/5(x-2)=3
. 2x 1/3-2x-4/3=3
. 10x 5-6x 12/15=3/1
. Cross multiple
. 4x 17=45 . 4x/4=28/4
. x=7. 3)
. Apply 5m rule to find C P
. t/sin T = P/sin P
. t/sin 110 = 6/sin 40
. t=6 * 0.9396/0.6428
. =56376/6.6428 . =87704
. =877km 4)
. Total Fruit = 80 60 = 140 (a)
. (i) Pr one of each fruit is picked
. (79/140 *60/139) ( 59/140 * 80/139)
. =4740/19,460 4720/19,460
. =9460/19,460 = 0.486 4aii)
. Pr one type of fruit is picked
. (79/140 * 78/139) (39/140 * 5p/139)
. =6162/19,460 3422/19,460
. = 9584/19,460 = 0.492 4b)
. 5X/8 - 1/6 ≤ X/3 7/24
. Multiply through by 24 i:e
. 15X - 4 ≤ 8X 7
. 15X - 8X ≤ 7 4
. 7X = 11 . X ≤ 11/7 ===> X ≤ 1 4/9 5a)
. 3/X 2 - 6/3X - 1
. 3(3X - 1) - 6 (X 2)/ (X 2) ( 3X - 1)
. 9X - 3 - 6X - 12/(X 2)(3X - 1)
. 3X - 15/(X 2)(3X - 1) 5b)
. C.I=P[1 r/100]^
. =25000[1 12/100]^3
. =25000[1 0.12]^3
. =25000 * 1.4049
. =35122.50 . =N35,122.50 6a)
. X -3/2
. X=2/3 or X=2
. (X 3/2)^2 or (X -2)
. (X 3/2) (X - 2)
. X (X - 2) 3/2 (X - 2) . X^2 - 2X 3 X/2 - 3
. 2X^2 - 4X 3X - 6
2X^2 - X - 6 6b)
. h/h 8 = 6/10
. 10h = 6h 48
. h = 12
. H = h 8
. H = 12 8 . H = 20
. Volume = 1/3 A.h
. = 1/3 (10*10) * 20 - 432/3
. = 200/3 - 432/3
. =1568/3
. =522.67cm3 7a)titan/360×2pie r cos t
. d=55/360×2×22/7×640 cos 4
. d=55×44×6400 cos 4/2520
. d=55×44×6400×0496/2520
. d=15,449.28/2520
. d=6130.67 . d~6130km. ii)
distance along gent circle
. D=tita/360×2pie r
. D=55/360×2/7×22/7×6400/1
. D=55×44×6400/2520
. D=15,488×6400/2520 . D=6144.03
. D=~6146km. 7b)
. Length of sector tita/360×2pie r
. L=120/360×2/1×22/7×42/1
. L=120×44×42/2520
. L=221760/2520
. L=88cm . L=2pie r
. Where r is the radius of circumference
. 88=2×22/7×r
. 88×7=44r
. R=88×7/44
. R=616/44 . R=14cm.
. Curved surface area = pie rc
. A=22/7×14×42/1
. A=22×14×4^2/7
. A=12936/7
. A=1848cm^2. 8a)
. X=60/t ---------->(i)
. Y=180/t ---------->(ii)
. T1=60/X
. T2=100/Y
. T1 T2=5 . 60/X 180/Y = 300 ---------->(i)
. 180/X 60/Y = 260 ---------->(ii)
. Let P =1/X
. 2 = 1/Y
. 60p 180 Q = 300
. 180p 6Q = 200 . P 3Q =5
. 9P 3Q =13
. Substract (i)from (ii)
. 8p = 8
. P = 8/8 ÷ P = 1
. Subtract P into (i) . P 3Q =5
. 1 3Q =5
. 3Q =5-1
. 3Q =4
. Q = 4/3
. P = 1 ÷ 1 = 1/X ÷ X = 1 . 4/3 = 1/Y ÷ Y = 3/4 8b)
. 2001 --------- 25,700
. 2002 --------- 15/100 X 25,700 25,700 = 29,555
. Amount of tax in 2002
. = 29,555 * 12.5/100
. = N3694.375 . =N3690 8c)
. Log25
. Log16 25/100
. Log16 2/4
. Log4 6-1
. -1/2 Log4^4 . -1/2 9ai)
. W=K C/2
. 24 = k C/16
. 384 = 16K C -------(i)
. 18 = K C/4
. 72 4K C ---------(ii) . 16K C = 384
. 4K C = 72
. Substact (ii) from (i)
. 12k/12 = 312/12
. K = 26
. Substract K into (i) . 16k C = 384
. C = 384 - 416
. C = -32
. W=k C/t2
. W=26-32/t2 (ii)
. When W= -46,t=?
. -46 = 26 -32/t2
. t2 = -32/-72
. t = Sqrt 16/36 = 4/6
. =2/3 9b)
. V = Pie r2 . d = 14,r = 7cm
. 1232 = 22/7 * 7^2 * h
. h = 7*1232/22*49
. h = 8624/1074
. h = 8cm 11a)
. y^1=x^2(3x 1)^2
. v=(2x 1)^2
. v=m^2
. dm/dx=2
. dv/dm=2m . dy/dx=dv/dm×dm/dx
. =2m×2
. =4m
. dy/dx=4(2x 1)
. dy/dx=udv/dx v whole no. dy/dx
. =x^2 4(xx 1)^2,×3x . =4x^2(2x 1) 2x(2x 1)^2. 11b)
. [3 3 -1]
. [1 0 2]
. [3 -2 3]
. 2[0-(-4)-3[63]
. -1(-2) . 8 9 2
. =19. 11c)
. m=y2-y1/x2-x1
. y-y1= m(x-x2)
. m=4-3/-1-2
. m=-1/3
. y1-y2=-1/3(x-x2) . y-3=1/3(x-2)
. y-3=-4/3 2/3
. 3y=-x 11
. y=-1/3x 11/3.
0 comments:
Post a Comment